Answer:
Option b) Gina's systolic blood pressure is 1.50 standard deviations above the average systolic blood pressure of women her age. Â Â Â Â Â Â
Step-by-step explanation:
We are given the following in the question:
The distribution of systolic blood pressure of other women is a bell shaped distribution that is a normal distribution.
z-score = 1.50
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
Let x be the Gina's systolic blood pressure.
Thus, we can write:
[tex]1.50 = \displaystyle\frac{x-\mu}{\sigma}\\\\x = 1.5\sigma + \mu \\\text{where }\sigma \text{ is the standard deviation and }\\\mu \text{ is the mean for the given distribution of blood pressure.}[/tex]
Thus, we can write Gina's blood pressure  is 1.50 standard deviations above the average systolic blood pressure of women her age.
Option b) Gina's systolic blood pressure is 1.50 standard deviations above the average systolic blood pressure of women her age.