Answer:
1315789.47368 lines/m
Explanation:
m = Order = 1
[tex]sin\theta[/tex] = 1 For maximum condition
[tex]\lambda[/tex] = Wavelength = 760 nm maximum
From Rayleigh criteria we have the expression for the gap
[tex]d=\dfrac{m\lambda}{sin\theta}\\\Rightarrow d=\dfrac{1\times 760}{1}\\\Rightarrow d=760\ nm[/tex]
The number of lines is the reciprocal of the slit distance
[tex]n=\dfrac{1}{d}\\\Rightarrow n=\dfrac{1}{760\times 10^{-9}}\\\Rightarrow n=1315789.47368\ /m[/tex]
The number of lines is 1315789.47368 per meter
