contestada

A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0%H2SO4 by mass and has a density of 1.84 g/mL.

Part A

Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to neutralize 6.05×103 kg of sulfuric acid solution?

Express your answer with the appropriate units

Respuesta :

Answer:

6,216.684 kilograms of sodium carbonate must be added to neutralize [tex]6.05\times 10^3 kg[/tex] of sulfuric acid solution.

Explanation:

Mass of sulfuric acid solution = [tex]6.05\times 10^3 kg=6.05\times 10^6 g[/tex]

[tex]1 kg = 10^3 g[/tex]

Percentage mass of sulfuric acid = 95.0%

Mass of sulfuric acid = [tex]\frac{95.0}{100}\times 6.05\times 10^6 g[/tex]

[tex]=5,747,500 g[/tex]

Moles of sulfuric acid = [tex]\frac{5,747,500 g}{98 g/mol}=58,647.96 mol[/tex]

[tex]H_2SO_4+Na_2CO_3\rightarrow Na_2SO_4+CO_2+H_2O[/tex]

According to reaction , 1 mole of sulfuric acid is neutralized by 1 mole of sodium carbonate.

Then 58,647.96 moles of sulfuric acisd will be neutralized by :

[tex]\frac{1}{1}\times 58,647.96 mol=58,647.96 mol[/tex] of sodium carbonate

Mass of 58,647.96 moles of sodium carbonate :

[tex]106 g/mol\times 58,647.96 mol=6,216,683.76 g[/tex]

6,216,683.76 g = 6,216,683.76 × 0.001 kg = 6,216.684 kg

6,216.684 kilograms of sodium carbonate must be added to neutralize [tex]6.05\times 10^3 kg[/tex] of sulfuric acid solution.

okpalawalter8

We have that for the Question "How many kilograms of sodium carbonate must be added to neutralize 6.05×103 kg of sulfuric acid solution" it can be said that

  • 5748 kg of H2SO4 =6217 kg of Na_2CO_3

From the question we are told

  • A tanker truck carrying 6.05×103 kg of concentrated sulfuric acid solution tips over and spills its load. The sulfuric acid solution is 95.0%H2SO4 by mass and has a density of 1.84 g/mL.  

 

  • Sodium carbonate (Na2CO3) is used to neutralize the sulfuric acid spill. How many kilograms of sodium carbonate must be added to neutralize 6.05×103 kg of sulfuric acid solution?

Generally the equation for the 95% mass of sulfuric acid  is mathematically given as

[tex]95\% \ mass \ of\ sulfuric\ acid= 6.05*1000*0.95[/tex]

[tex]95\% \ mass \ of\ sulfuric\ acid = 5748g[/tex]

Therefore

The resultant equation

[tex]Na_2CO_3+ H_2SO_4 >>>> Na_2SO_4+ H_2O+CO_2[/tex]

Therefore

with the appropriate molar masses we discover that

106 kg of [tex]Na_2CO_3[/tex]  needs 98 kg of [tex]H_2SO_4[/tex] for a reaction to take place

Therefore

[tex]5748 kg\ of\ H2SO4 =\frac{5747.5*106}{98}[/tex]

5748 kg of H2SO4 =6217 kg of Na_2CO_3

For more information on this visit

https://brainly.com/question/23379286

Otras preguntas