Line CD passes through point E.
Line CD: y−5=−3(x+2)
Point E: (6,−1)
What is the equation of the line that is perpendicular to line CD?

Respuesta :

The equation of the perpendicular line to line CD and passes through point E is y = [tex]\frac{1}{3}[/tex] x - 3

Step-by-step explanation:

The relation between the slopes of the perpendicular lines is

  • The product of their slopes is -1
  • If the slope of one of them is a, then the slope of the other is [tex]-\frac{1}{a}[/tex]
  • To find the slope of the perpendicular line to a given line reciprocal the slope of the given line and change its sign

The form of the linear equation is y = m x + b, where m is the slope of the line and b is the y-intercept

∵ The equation of line CD is y - 5 = -3(x + 2)

- Let us put it in the form of y = m x + b to find its slope m

∴ y - 5 = -3(x) + -3(2)

∴ y - 5 = -3x + -6

∴ y - 5 = -3x - 6

- Add 5 to both sides

∴ y = -3x - 1

- The slope of the line in this form is the coefficient of x

∴ m = -3

∴ The slope of the given line CD is -3

To find the slope of the perpendicular line on line CD reciprocal the slope of the line CD and change its sign

∵ The reciprocal of -3 is [tex]-\frac{1}{3}[/tex]

- Change its sign

∴ The slope of the perpendicular line to line CD is [tex]\frac{1}{3}[/tex]

- Substitute it in the form of the equation

∴ y = [tex]\frac{1}{3}[/tex] x + b

- To find b substitute x and y in the equation by the coordinates

  of a point on the line

∵ The perpendicular line to line CD passes through point E

∵ The coordinates of point E is (6 , -1)

∴ x = 6 and y = -1

∵ -1 =  [tex]\frac{1}{3}[/tex] (6) + b

∴ -1 = 2 + b

- Subtract 2 from both sides

∴ -3 = b

- Substitute it in the equation

∴ y = [tex]\frac{1}{3}[/tex] x + (-3)

∴ y = [tex]\frac{1}{3}[/tex] x - 3

The equation of the perpendicular line to line CD and passes through point E is y = [tex]\frac{1}{3}[/tex] x - 3

Learn more:

You can learn more about the perpendicular line in brainly.com/question/2601054

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