Respuesta :
Answer:
a) 2622.903 N/m^3
b) 1.38233
c)4.878811765
Explanation:
Find the void ratio using the formula:
[tex]y = \frac{G_{s}*y_{w} + w*G_{s}*y_{w} }{1+e} ....... Eq1[/tex]
Here;
[tex]G_{s}[/tex] is specific gravity of soil solids
[tex]y_{w}[/tex] is unit weight of water = 998 kg/m^3
[tex]w[/tex] is the moisture content = 0.17
[tex]e[/tex] is the void ratio
[tex]y[/tex] is the unit weight of soil = 14.9KN/m^3
Saturation Ratio Formula:
[tex]w*G_{s} = S*e ..... Eq2[/tex]
S is saturation rate
Substitute Eq 2 into Eq 1
[tex]y = \frac{(\frac{S*e}{w}) * y_{w} + S*e*y_{w} }{1+e}[/tex]
[tex]14900 = \frac{3522.352941*e + 598.8*e }{1+e} = \frac{4121.152941*e}{1+e}\\\\ e= 1.38233[/tex]
Specific gravity of soil solids
[tex]G_{s} = \frac{S*e}{w} = \frac{0.6*1.38233}{0.17} = 4.878811765[/tex]
Saturated Unit Weight
[tex]y_{s} = \frac{(G_{s} + e)*y_{w} }{1+e} \\=\frac{(4.878811765 + 1.38233)*998 }{1+1.38233}\\\\= 2622.902571 N/m^3[/tex]
