Respuesta :
Answer:
[tex]\large \boxed{\text{ 0.4 lb/ft}^{3}; 5}[/tex]
Step-by-step explanation:
1. Density
[tex]\begin{array}{rcl}\text{Density} & = & \dfrac{\text{Mass}}{\text{Volume}}\\\\& = & \dfrac{\text{4 lb}}{\text{10 ft}^{3}}\\\\& = &\textbf{0.4 lb/ft}^{\mathbf{3}}\\\end{array}\\\text{The density of the gas is $\large \boxed{\textbf{ 0.4 lb/ft}^{\mathbf{3}}}$}[/tex]
2. Specific gravity
Specific gravity (sp gr) is the ratio of the density of the density of a gas to the density of dry air at standard temperature and pressure.
At IUPAC standard temperature and pressure (0 °C and 100 kPa), dry air has a density of 0.080 lb/ft³.
[tex]\begin{array}{rcl}\text{Sp gr}& = & \dfrac{\rho_{\text{gas}}}{\rho_{\text{dry air}}}\\\\& = & \dfrac{\text{0.4 lb/ft}^{3}}{\text{0.080 lb/ft}^{3}}\\\\& = &\mathbf{5}\\\end{array}\\\text{The specific gravity of the gas is $\large \boxed{\mathbf{5}}$}[/tex]
The density is the ratio of mass to volume, while the specific gravity is the ratio of two densities
The values required are;
- Density of the gas is 0.4 lb/ft.³
- The specific gravity of the gas is approximately 5.23
Given:
Mass of the gas = 4 lb
Volume occupied by the gas = 10 ft.³
Required:
Find the density and the specific gravity of the gas
Density:
[tex]Density = \dfrac{Mass}{Volume}[/tex]
Therefore, the density of the mass of gas is given as follows;
[tex]Density = \dfrac{4 \ lb}{10 \ ft.^3} = 0.4 \ lb/ft.^3[/tex]
The density of the gas = 0.4 lb/ft.³
Specific gravity:
The specific gravity, s.g. of a gas is the ratio of the density of the gas to the density of air
The density of air ≈ 0.0765 lb/ft.³
The specific gravity of the gas is therefore;
[tex]s.g. = \dfrac{0.4 \ lb/ft.^3}{0.0765 \ lb/ft.^3} = \dfrac{800}{153} \approx 5.23[/tex]
The specific gravity of the gas is approximately 5.23
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