Answer: The required equation for points P is [tex]4x+2y=17.[/tex]
Step-by-step explanation: We are give two points A(0, 1, 2) and B(6, 4, 2).
To find the equation for points P such that the distance of P from both A and B are equal.
We know that the distance between two points R(a, b, c) and S(d, e, f) is given by
[tex]RS=\sqrt{(d-a)^2+(e-b)^2+(f-c)^2}.[/tex]
Let the point P be represented by (x, y, z).
According to the given information, we have
[tex]PA=PB\\\\\Rightarrow \sqrt{(x-0)^2+(y-1)^2+(z-2)^2}=\sqrt{(x-6)^2+(y-4)^2+(z-2)^2}\\\\\Rightarrow x^2+y^2-2y+1+z^2-4z+4=x^2-12x+36+y^2-8y+16+z^2-4z+4~~~~~~~[\textup{Squaring both sides}]\\\\\Rightarrow -2y+1=-12x-8y+52\\\\\Rightarrow 12x+6y=51\\\\\Rightarrow 4x+2y=17.[/tex]
Thus, the required equation for points P is [tex]4x+2y=17.[/tex]
