Answer:
16 KJ Â or 16,720 J energy has gained by the water.
Explanation:
Given data:
Mass of water = m = 100 g
Temperature difference = ΔT=  (60 - 20)∘C
specific heat of water 1 calorie = Â c = Â 4.18 J
To find:
Heat absorbed by water = q=?
Formula:
q =  m . c .  ΔT
Solution:
q = (100 g) x (4.18J/g ∘C) x  (60 - 20)∘C
 = 16,720 J