Given: m∠AEB = 45° ∠AEC is a right angle. Prove: bisects ∠AEC. Proof: We are given that m∠AEB = 45° and ∠AEC is a right angle. The measure of ∠AEC is 90° by the definition of a right angle. Applying the gives m∠AEB + m∠BEC = m∠AEC. Applying the substitution property gives 45° + m∠BEC = 90°. The subtraction property can be used to find m∠BEC = 45°, so ∠BEC ≅ ∠AEB because they have the same measure. Since divides ∠AEC into two congruent angles, it is the angle bisector.

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dodgechalleger dodgechalleger · Answer 1 · 2018-03-17T17:01:54+01:00

the answer to the question is angle Angle addition postulate hope i helped

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SerenaBochenek SerenaBochenek · Answer 2 · 2019-01-15T08:09:24+01:00

Answer:

The proof is explained below.

Step-by-step explanation:

Given ∠AEB=45° and also ∠AEC is right angle i.e ∠AEC=90°

we have to prove that EB is the angle bisector.

In the right angled triangle AEC,

∠AEC=90° and also ∠AEB=45°

∵ ∠AEB+∠BEC=∠AEC

⇒ 45° + ∠BEC = 90°

By subtraction property of equality

∠BEC = 45°

Hence, ∠AEB = ∠BEC = 45°

The angle ∠AEB equally divides by the line segment EB therefore, the line segment EB is the angle bisector of angle ∠AEB.