Respuesta :
Answer: The molar mass of the protein is 15394.2 g/mol
Explanation:
To calculate the concentration of solute, we use the equation for osmotic pressure, which is:
[tex]\pi=iMRT[/tex]
where,
[tex]\pi[/tex] = osmotic pressure of the solution = 0.118 atm
i = Van't hoff factor = 1 (for non-electrolytes)
M = molarity of solute = ?
R = Gas constant = [tex]0.0821\text{ L atm }mol^{-1}K^{-1}[/tex]
T = temperature of the solution = [tex]25^oC=[273+25]=298K[/tex]
Putting values in above equation, we get:
[tex]0.118atm=1\times M\times 0.0821\text{ L.atm }mol^{-1}K^{-1}\times 298K\\\\M=\frac{0.118}{1\times 0.0821\times 298}=4.82\times 10^{-3}M[/tex]
To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:
[tex]\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}[/tex]
We are given:
Molarity of solution = [tex]4.82\times 10^{-3}M[/tex]
Given mass of protein = 371. mg = 0.371 g (Conversion factor: 1 g = 1000 mg)
Volume of solution = 5.00 mL
Putting values in above equation, we get:
[tex]4.82\times 10^{-3}M=\frac{0.371\times 1000}{\text{Molar mass of protein}\times 5.00}\\\\\text{Molar mass of protein}=\frac{0.371\times 1000}{4.82\times 10^{-3}\times 5.00}=15394.2g/mol[/tex]
Hence, the molar mass of the protein is 15394.2 g/mol
Answer:
mm protein = 15365.8183 g/mol
Explanation:
∴ molar mass (mm) ≡ g/mol
- osmotic pressure (π) = C RT
∴ π = 0.118 atm
∴ T = 25°C ≅ 298 K
∴ concentration (C ) [=] mol/L
∴ mass protein = 371 mg = 0.371 g
∴ volume sln = 5.00 mL = 5 E-3 L
⇒ C = π / RT = (0.118 atm)/((0.082 atm.L/K.mol)(298 K))
⇒ C = 4.8289 E-3 mol/L
⇒ mol protein = (4.8289 E-3 mol/L)×(5 E-3 L) = 2.4145 E-5 mol
⇒ mm protein = (0.371 g)/(2.4145 E-5 mol) = 15365.8183 g/mol
