Respuesta :
Answer: b. 134
Step-by-step explanation:
Given : A minimum usual value of 135.8 and a maximum usual value of 155.9.
Let x denotes a usual value.
i.e. 135.8< x < 155.9
Therefore , the interval for the usual values is [135.8, 155.9] .
If interval for any usual value is [135.8, 155.9] , then any value should lie in this otherwise we call it unusual.
Let's check all options
a. 137 ,
since 135.8< 137 < 155.9
So , it is usual.
b. 134
since 134<135.8 (Minimum value)
So , it is unusual.
c. 146
since 135.8< 146 < 155.9
So , it is usual.
d. 155
since 135.8< 1155 < 155.9
So , it is usual.
Hence, the correct answer is b. 134 .
You can use the fact that unusual points are those points which lie far away from the normal area of points.
The value which would be considered unusual is given by
Option b: 134
How to determine unusual points (also called anomalies or outliers) ?
Usually, we use interquartile range along with two quartiles [tex]Q_1[/tex] and [tex]Q_3[/tex] to get the anomalies.
Those values who lie below [tex]Q_1 - 1.5 \times IQR[/tex] or above [tex]Q_3 + 1.5 \times IQR[/tex] are called anomalies.
But since in the case when these things are not obtainable, we check manually which point is lying away from mean or outside of usual range etc.
How to find if a point is lying outside a range?
Suppose that minimum usual value is given to be 'a' and the maximum usual value be 'b', then it is written as interval [a,b]
If some value is lying outside this range of values (the spread from a to b), then it means it is either smaller than minimum which is < a, or bigger than maximum of that range which is > b.
Using above definitions to find the unusual number
Since the given usual minimum value is 135.8
and the given usual maximum value is 155.9
thus, the range of usual value is [135.8, 155.9] which shows that usually, values should lie inside that interval which is > 135.8 and < 155.9
All options except the second options lie in the interval.
For second option, we have 134 < 135.8
thus, this value being smaller than usual minimum value, thus, it will be considered unusual.
Thus,
The value which would be considered unusual is given by
Option b: 134
Learn more about outliers here:
https://brainly.com/question/10219729
