Paul was asked to use the elmination to find the solution to the system of linear equations
5x + 4y = 1
−2x − 8y = −26
What are the missing steps in his work below?
5x + 4y = 1 −2x − 8y = −26
10x + 8y = 2 + (−2x −8y = −26) 8x + 0y = −24 8x = −24 x = −3 5x + 4y = 1 5(−3) + 4y = 1 −15 + 4y = 1 4y = 16
y = 4 Select one: A. 5x + 4y = 1 + (−2x − 8y = −26)
B. 2⋅[5x + 4y = 1] 10x + 8y = 2
C. 5x + 4y = 1 − (−2x − 8y = −26)
D. −5⋅[−2x − 8y = −26] 10x + 40y = 130