Answer:
c
Step-by-step explanation:
The mean value theorem states that for a continuous and differentiable function on a interval there exists a number c from that interval, that
[tex]f'(c)=(f(b)-f(a))/(b-a)[/tex]
First we must determine the endpoints:
[tex]f(49)=-119[/tex]
[tex]f(4)=-4[/tex]
We find the derivative of the function, f'(c)
[tex]f'(c)=3+2\sqrt{c}[/tex]
Therefore:
[tex]3+2\sqrt{c}=((-119)-(-4))/((49)-(4))[/tex]
Simplify:
[tex]3+2\sqrt{c}=-23/9[/tex]
[tex]c=81/4[/tex]