Answer: The concentration of carbon monoxide is [tex]0.22\times 10^{-6}lb/ft^3[/tex]
Explanation:
Given: [tex]3.5\times 10^{-6}g[/tex] of carbon monoxide is present in 1L of air.
[tex]454g=1lb[/tex]
[tex]1g=\frac{1}{454}\times 1=0.0022lb[/tex]
[tex]3.5\times 10^{-6}g=\frac{0.0022}{1}\times 3.5\times 10^{-6}g=0.0077\times 10^{-6}lb[/tex]
[tex]1L=0.035ft^3[/tex]
[tex]\frac{3.5\times 10^{-6}g}{1L}=\frac{0.0077\times 10^{-6}lb}{0.035ft^3}=0.22\times 10^{-6}lb/ft^3[/tex]
Thus the concentration of carbon monoxide is [tex]0.22\times 10^{-6}lb/ft^3[/tex]
