Respuesta :
Answer:
0.000273 M
Explanation:
Henry's states that at constant temperature the amount of a gas that dissolves in a liquid is directly proportional to the partial pressure in of that gas in equilibrium with that liquid.
Pressure of Oxygen = mole fraction of Oxygen × 1.00 atm
Mole fraction Oxygen = 21/100 × 1.00atm = 0.21 atm
Molar solubility of Oxygen = KH × PO2 = 0.0013 × 0.21 = 0.000273 M
The amount of a gas that dissolves in a liquid is proportional to the partial pressure of the gas above the liquid. Solubility of oxygen in water exposed to air at 1.00 atm is 0.000273 M.
Henry's Law:
It states that at constant temperature the amount of a gas that dissolves in a liquid is proportional to the partial pressure of the gas above the liquid.
C = k P
Where,
C = concentration of a dissolved gas
k = Henry's Law constant = 0.0013 M/atm.
P = partial pressure of the gas = [tex]\bold {\dfrac {21}{100} \times 1.00\ atm = 0.21\ atm}[/tex]
Put the values in the formula,
[tex]\bold {C = 0.0013 \times 0.21 = 0.000273\ M }[/tex]
Therefore, solubility of oxygen in water exposed to air at 1.00 atm is 0.000273 M.
To know more about Henry's Law,
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