Respuesta :
Number of possible outcome for tossing N coins = [tex]2^N[/tex]
Solution:
Possible outcomes when tossing one coin = {H, T}
Number of possible outcomes when tossing one coin = 2 [tex]=2^1[/tex]
Possible outcomes when tossing two coins = {HH, HT, TH, TT}
Number of possible outcomes when tossing two coins = 4 [tex]=2^2[/tex]
Possible outcomes when tossing three coins
= {HHH, HHT, HTH, THH, TTH, THT, HTT, TTT}
Number of possible outcomes when tossing three coins = 8 [tex]=2^3[/tex]
Therefore, the sequence obtained is [tex]2^1, 2^2, 2^3[/tex].
If continue this sequence, we can obtain number of possible outcome for tossing N coins is [tex]2^N[/tex].
Answer:
Number of possible outcome for tossing N coins = 2n
Step-by-step explanation:
