Answer:
1328.7032 kg
Explanation:
P = Pressure = 112 kPa
T = Temperature = 285 K
V = Volume = 7023 m³
R = Gas constant = 8.314 J/mol K
From the ideal gas law we have
[tex]PV=nRT\\\Rightarrow n=\dfrac{PV}{RT}\\\Rightarrow n=\dfrac{112000\times 7023}{8.314\times 285}\\\Rightarrow n=331960.04203\ moles[/tex]
The mass of gas is given by
[tex]m=n\times MW_{He}\\\Rightarrow m=331960.04203\times 4.0026\times 10^{-3}\\\Rightarrow m=1328.70326\ kg[/tex]
The mass of helium in the blimp is 1328.7032 kg
