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If you weigh 675 N on the earth, what would be your weight on the surface of a neutron star that has the same mass as our sun and a diameter of 21.0 km?

Respuesta :

Answer:

8.29 * 10^{13} N

Explanation:

Weigth is the force of gravity a body of mass experiences due to the gravity of another mass.

Force=mass*acceleration (to calculate the mass of the object);

675=m*9.8; Mass = 68.88 kg

Force= [tex]\frac{GMm}{r^{2} }[/tex]; M is the mass of the bigger object, m is the mass of the smaller object, r is the seperation in between (radius in this case) and G is the Gravitational constant.

Mass of the sun = 1.989 × 10^30 kg

G = 6.67 × 10-11 m3 kg-1 s-2

mass of the object = 68.88 kg;

Applying the formula:

Force=[tex]\frac{(6.67 * 10^{-11} ) * (68.88) * (1.989 * 10^{30} )}{(((21 *10^{3} ))/2)^{2} }[/tex]

Force = 8.29 * 10^{13} N

The weight on the surface of a neutron star that has the same mass as our Sun and a diameter of 21.0 km will be 8.29 × 10¹³ N

Gravitational force:

Given that the weight of the person on the earth is 675N.

mg = 675N

where m is the mass of the person.

m = 675/g

m = 675/9.8

m = 68.87 kg

The gravitational force on the surface of a celestial body is given by:

F = GMm/R²

where G is the gravitational constant

M is the mass of the body

m is the mass of the person

and, R is the radius of the body

F = (6.67 × 10⁻¹¹)( 2 × 10³⁰)(68.87) / (21/2 × 10³)²

F = 8.29 × 10¹³ N

Learn more about gravitational force:

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