In the morning, when the temperature is 286 K , a bicyclist finds that the gauge pressure in his tires is 404 kPa . That afternoon she finds that the pressure in the tires has increased to 422 kPa .
Part A What is the afternoon temperature?

Respuesta :

Answer:

The answer is 298.74K

Explanation:

Ideal gas formula is following:

[tex]P*V=n*R*T[/tex]

We are assuming that, except temperature and pressure, all other variables are constant. So if we define morning temperature and pressure as:

[tex]T_{0}=286K\\P_{0}=404kPa[/tex]

Then if we write the same formula for afternoon time the equation will be:

[tex]P_{1}*V=n*R*T_{1}\\1.045*P_{0}*V=n*R*T_{1}[/tex]

Then we find out that the must be correlation between morning and afternoon temperature as following:

[tex]T_{1}=1.045*T_{0}\\T_{1}=1.045*286\\T_{1}=298.74K[/tex]