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Ammonium Iodide dissociates reversibly to ammonia and hydrogen iodide:
NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C
Calculate the partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C.
A.0.103 atm
B.0.215 atm
C.0.232 atm
D.0.464 atm
E.2.00 atm

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agboanthony124

Answer:

The partial pressure of ammonia at equilibrium when a sufficient quantity of ammonium iodide is heated to 400°C Is 0.103 atm.

The correct option is A.

Explanation;

NH4I(s) ⇋ NH3(g) + HI(g)Kp = 0.215 at 400°C

NH4I(s)= 0.215

NH3(g)=0.103

HI(g)Kp=0.112

Therefore = 0.103 +0.112= 0.215

Therefore the partial pressure of ammonia at equilibrium is 0.103 atm

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