Answer:
d) 0.0132
Step-by-step explanation:
In a sample of size n, with proportion p, the standard error of the proportion is:
[tex]SE_{p} = \sqrt{\frac{p(1-p)}{n}}[/tex]
In this problem, we have that:
[tex]p = 0.26, n = 1100[/tex]
So
[tex]SE_{p} = \sqrt{\frac{p(1-p)}{n}} = \sqrt{\frac{0.26*0.74}{1100}} = 0.0132[/tex]
So the correct answer is:
d) 0.0132