Respuesta :
170 ml of 20 % fungicide solution is mixed with 30 ml of 60% fungicide solution to create 200 milliliters of a 26% solution
Solution:
The final solution has 200 ml
Let "x" be the ml of 20 % fungicide solution
Then, (200 - x) is the ml of 60% fungicide solution
Then according to question, we can say,
"x" ml of 20 % fungicide solution is mixed with (200 - x) ml of 60% fungicide solution to get 200 ml of 26 % solution
We can frame a equation as:
[tex]x \times 20 \% + (200-x) \times 60 \% = 200 \times 26 \%\\\\\text{Solve the equation for "x" }\\\\x \times \frac{20}{100} + (200-x) \times \frac{60}{100} = 200 \times \frac{26}{100}\\\\\text{Simplify the above expression}\\\\x \times 0.2 + (200-x) \times 0.6 = 26 \times 2\\\\0.2x + 120 - 0.6x = 52\\\\-0.4x = 52 - 120\\\\-0.4x = -68\\\\x = 170[/tex]
Thus 170 ml of 20 % fungicide solution is used
Then , (200 - x) = 200 - 170 = 30 ml of 60% fungicide solution is used
