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Answer:
The of getting an even number in first and an odd number second is [tex]\frac{1}{4}\ or\ 0.25[/tex].
Step-by-step explanation:
Given,
Total number of outcomes = 36
We have to find the probability of rolling an even number first and an odd number second.
Solution,
Firstly we will find out the possible outcomes;
[tex](2,1),\ (2,3),\ (2,5),\ (4,1),\ (4,3),\ (4,5),\ (6,1),\ (6,3),\ (6,5),[/tex]
So the total number of outcomes = 9
Now according to the formula of probability, which is;
[tex]P(E)=\frac{\textrm{total number of possible outcomes}}{\textrm{total number of outcomes}}[/tex]
Now on putting the values, we get;
P(of getting an even number in first and an odd number second)=[tex]\frac{9}{36}=\frac{1}{4}=0.25[/tex]
Hence The of getting an even number in first and an odd number second is [tex]\frac{1}{4}\ or\ 0.25[/tex].
