Answer:
6 seconds
Step-by-step explanation:
1/12 mile * 5280 feet/mile = 440 feet per train
50 miles/hour * 1/3600 hr/sec * 5280 ft/mile = 73 1/3 ft/second
one train has to travel 440 feet to pass the other train
440 feet * 1/(73 1/3) sec/ft = 6 seconds
The time it will take for the two trains to pass each other's rear car is 6 seconds.
The speed is the distance covered by an object at a particular time. Therefore, it is the ratio of distance and time.
[tex]\rm{Speed = \dfrac{Distance}{Time}[/tex]
Two passenger trains travelling in opposite directions meet and pass each other. Each train is 1/12 miles long and is traveling 50 mph.
Therefore, the total distance that the two train needs to cover is twice the size of a train.
Distance = 2 × 1/12miles = 1/6 miles
Also, the relative speed of the two trains moving in opposite directions is,
Speed = 50 mph + 50 mph = 100 mph
Now, the time that the two trains need to cover the entire distance is,
Time = (1/6 miles)/ 100mph = 1/600 hours
Converting the time to seconds,
Time = 1/600 hours × 3600 = 6 seconds
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