A 0.50 kg croquet ball is initially at rest on the grass. When theball is struck by a mallet, the average force exerted on it is240 N. If the ball's speed after beingstruck is 3.0 m/s, how long was the malletin contact with the ball?

Respuesta :

Answer:

time=6.25×10⁻³ seconds

or

time=6.25 Milliseconds

Explanation:

Given Data

Ball mass= 0.50 kg

Force = 240 N

Speed =3.0 m/s

To find

Time

Solution

From Newtons second Law of motion

Force=mass×acceleration

As mass and Force is given we need to Find acceleration

So

Acceleration=Force/mass

Acceleration=240/0.50

Acceleration=480 m/s²

When ball was at rest its velocity at that time was 0.Now the final velocity is given as:

Velocity=acceleration×time

As we have find the acceleration and velocity is given so we can find time easily

So

time=velocity/acceleration

time=(3.0m/s)/480 N

time=6.25×10⁻³ seconds

or

time=6.25 Milliseconds

Velocity is a vector quantity. It takes  6.25×10⁻³ seconds, malletin contact with the ball.

 

Given here,  

Ball mass = 0.50 kg  

Force = 240 N  

Velocity = 3.0 m/s

The formula of the time,

[tex]\bold {t = \dfrac va }[/tex]

Where,

t - time

v - velocity = 0.3 m/s

a - acceleration [tex]\bold { = \dfrac fm = \dfrac {240 }{0.5} = 480\ m/s^2}[/tex]

Put the values in the formula,

[tex]\bold {t = \dfrac { 3}{480}}\\\\\bold {t = 6.25x10^-^3}[/tex]

Therefore, it takes  6.25×10⁻³ seconds, malletin contact with the ball.

To know more about Velocity,

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