Respuesta :
Determine first the common ratio (r) of the geometric sequence by,
r = (t5 / t3)^(1/(5 - 3))
Substituting the known values from the given,
r = (3750 / 150)^(1/2) = 5
The sixth term may be obtained by multiplying the fifth term (t5 = 3750) by the common ratio. This is shown below,
t6 = (3750) x 5 = 18750
Thus, the 6th term of the geometric sequence is 18750.
r = (t5 / t3)^(1/(5 - 3))
Substituting the known values from the given,
r = (3750 / 150)^(1/2) = 5
The sixth term may be obtained by multiplying the fifth term (t5 = 3750) by the common ratio. This is shown below,
t6 = (3750) x 5 = 18750
Thus, the 6th term of the geometric sequence is 18750.
Answer:
The 6th term in the geometric sequence is either 18750 or -18750.
Step-by-step explanation:
Given information: In the given GP
[tex]t_3=150[/tex]
[tex]t_5=3750[/tex]
The nth term of a GP is
[tex]t_n=ar^{n-1}[/tex]
where, a is first term and r is common ratio.
Third term of the GP is 150, so
[tex]t_3=ar^{3-1}[/tex]
[tex]150=ar^2[/tex] .... (1)
Fifth term of the GP is 3750, so
[tex]t_5=ar^{5-1}[/tex]
[tex]3750=ar^4[/tex] .... (2)
Divide equation (2) by equation (1).
[tex]\frac{3750}{150}=\frac{ar^4}{ar^2}[/tex]
[tex]25=r^2[/tex]
[tex]\pm 5=r[/tex]
The value of common ratio is either 5 or -5.
Put the value of r² in equation (1).
[tex]150=a(25)[/tex]
[tex]6=a[/tex]
The first term of the GP is 6.
If the first term of GP is 6 and common difference is 5, then 6th term is
[tex]t_6=ar^{6-1}=ar^5=6(5)^5=18750[/tex]
If the first term of GP is 6 and common difference is -5, then 6th term is
[tex]t_6=ar^{6-1}=ar^5=6(-5)^5=-18750[/tex]
Therefore the 6th term in the geometric sequence is either 18750 or -18750.