nacmeddJullip
contestada

Consider the division of 8y2 – 12y + 4 by 4y.



What is the value of a and b?
a = 2y and b = 3
a = and b = –3y
a = 2y and b = –3
a = and b = 3y

Respuesta :

jhonyy9
8y^2 -12y +4 / 4y = 2y -3     so from this result that a=2y and b= - 3
8y^2
-------
   0   -12y
        -12y
      ---------
           0    4

hope i ve understood it right what wan being a and b because you dont wrote there in the text of this exercise 

so than the 3rd  choice is right 
cerverusdante

Notice that the dividend [tex] 8y^2-12y+4 [/tex] has tree terms with [tex] a=8y^2 [/tex], [tex] b=-12y [/tex], c[tex] c=4 [/tex]

Now, to divided our dividend [tex] 8y^2-12y+4 [/tex] by the monomial (single term) [tex] 4y [/tex], the easiest thing to do is divide each term of the dividend by the monomial:

[tex] 8y^2-12y+4 [/tex] ÷ [tex] 4y [/tex] = [tex] \frac{8y^2-12y+4}{4y} =\frac{8y^2}{4y} -\frac{12y}{4y} +\frac{4}{4y}= 2y-3+\frac{1}{y} [/tex]

After performing the division we get that now [tex] a=2y [/tex] and [tex] b=-3 [/tex]

We can conclude that the correct answer is a = 2y and b = –3

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