I am having trouble with the last question. “Suppose that y=2.5 when x=1.5. Write a formula that expresses y in terms of x.”

y=2x-0.5
Step-by-step explanation:
Given the expression of Δy in terms of Δx as;
Δy=4/2 Δx
Given y=2.5 and x =1.5 then substituting in the equation above will give;
y-2.5=2(x-1.5)
y-2.5=2x-3
y=2x-3+2.5
y=2x-0.5
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The expression of y in terms of x given that y = 2.5 and x = 1.5 is y = 2x - 0.5
In order to write y as a function of x, we will use the formula for calculating the equation of a line in the point-slope form expressed as:
y-y0 = m(x-x0) where:
m is the slope
(x0, y0) is any point on the given line,
From the graph, we know that:
[tex]\frac{\triangle y}{\triangle x} =\frac{4}{2}\\ \frac{\triangle y}{\triangle x} =2\\\frac{y-y_0}{x-x_0} = 2\\y-y_0=2(x-x_0)\\[/tex]
Given that x₀ = 1.5 and y₀ = 2.5
Substitute
[tex]y-2.5=2(x-1.5)\\y-2.5 = 2x - 3\\y = 2x-3+2.5\\y=2x-0.5\\[/tex]
This shows that the expression of y in terms of x is y = 2x - 0.5
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