Answer: 2,970
Step-by-step explanation:
The number of ways to arrange n things such that a things are identical , b things are identical , and so on is [tex]\dfrac{n!}{a!\cdot b!\cdot ....}[/tex] .
As per given , we have
Number of Geometry books = 2
Number of Algebra books = 8
Number of Pre-Calculus books =2
Total books = 2+8+2=12
Then, the number of ways to arrange them : [tex]\dfrac{12!}{2!\cdot 8!\cdot 2!}[/tex]
[tex]=\dfrac{12\times11\times10\times9\times8!}{2\times8!\times2}=2970[/tex]
Hence, the total number of ways to arrange 2 Geometry books, 8 Algebra books and 2 Pre-Calculus books is 2,970.
