Answer.
given,
distance moved, d = 126 m
time = 13 s
then turns abruptly and gallops halfway back in 5.0 s .
a) Average speed = ?
total distance = 126 m + 62 m
= 189 m
total time = 13 + 5 = 18 s
[tex]average\ speed = \dfrac{total\ distance}{total\ time}[/tex]
[tex]average\ speed = \dfrac{189}{18}[/tex]
[tex]average\ speed = 10.5 m/s[/tex]
b) average velocity of the entire trip
total displacement = 126 - 62 = 62 m
total time = 18 s
[tex]average\ velocity = \dfrac{total\ displacement}{total\ time}[/tex]
[tex]average\ velocity = \dfrac{62}{18}[/tex]
[tex]average\ velocity = 3.44\ m/s[/tex]