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A small sphere with a mass of 441 g is moving upward along the vertical +y-axis when it encounters an electric field of 5.00 N/C . If, due to this field, the sphere suddenly acquires a horizontal acceleration of 13.0 m/s², what is the charge that it carries?A) 1.15 CB) -1.15 CC) 1150 CD) -1150 C

Respuesta :

Answer: Option (A) is the correct answer.

Explanation:

It is known that the relation between force and electric field is as follows.

                           F = qE .......... (1)

where,      F = force

                q = charge

                E = electric field

Also, we know that,   F = ma ...... (2)

Hence, equating equation (1) and (2) as follows.

                   qE = ma

or,                q = [tex]\frac{ma}{E}[/tex]  

Therefore, putting the given values into the above formula as follows.

                     q = [tex]\frac{ma}{E}[/tex]  

                        = [tex]\frac{441 g \times 13.0 m/s^{2}}{5.0 N/C}[/tex]

                        = 1.1466 C        

                        = 1.15 C (approx)

Therefore, we can conclude that the charge carried by given charge is 1.15 C.

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