Answer:
10 mg/L: C₆H₆
10 ppm: C₆H₆
1.28×10⁻⁴ M : [C₆H₆]
Explanation:
A liter of water was found to contain 10 mg of benzene (C6H6).
This can be understood as mg/L concentration. 10 mg of benzene are contained in 1L of solution.
If we want to write concentration of ppm, we assume μg/mL
So let's convert 10 mg to μg
10 mg . 1000 = 10000 μg
and 1L = 1000 mL
So μg/mL → 10000 μg / 1000 mL = 10
Molarity is mol/L
We know that the volume is 1L so let's convert the 10 mg of benzene to moles. (mass (g) / molar mass)
0.01 g / 78 g/mol = 1.28×10⁻⁴ moles
