Respuesta :
Answer: The new pressure of the gas in Pa is 388462
Explanation:
Combined gas law is the combination of Boyle's law, Charles's law and Gay-Lussac's law.
The combined gas equation is,
[tex]\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}[/tex]
where,
[tex]P_1[/tex] = initial pressure of gas at STP = [tex]10^5Pa[/tex]
[tex]P_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex] = initial volume of gas = 700.0 ml
[tex]V_2[/tex] = final volume of gas = 200.0 ml
[tex]T_1[/tex] = initial temperature of gas = 273 K
[tex]T_2[/tex] = final temperature of gas = [tex]30^oC=273+30=303K[/tex]
Now put all the given values in the above equation, we get:
[tex]\frac{10^5\times 700.0ml}{273K}=\frac{P_2\times 200.0ml}{303K}[/tex]
[tex]P_2=388462Pa[/tex]
The new pressure of the gas in Pa is 388462
The new pressure of the gas is 388462 Pa. The pressure of the gas in the system can be calculated by the combination of gas laws.
How to calculate the pressure of the gas?
The pressure of the gas in the system can be calculated by the combination of gas laws that is used for an ideal gas at STP.
[tex]\dfrac {P_1V_1}{T_1} =\dfrac {P_2V_2}{T_2}[/tex]
Where,
[tex]P_1[/tex] = initial pressure of gas at STP = [tex]10^5 Pa.[/tex]
[tex]V_2[/tex] = final pressure of gas = ?
[tex]V_1[/tex]= initial volume of gas = 700.0 ml
[tex]V_2[/tex]= final volume of gas = 200.0 ml
[tex]T_1[/tex] = initial temperature of gas = 273 K
[tex]T_2[/tex] = final temperature of gas = 30°C = 303 K
Put the values in the formula,
[tex]\dfrac {10^5 \times 700 }{273 } =\dfrac {P_2\times200 }{ 303}\\\\P_2 = 388462 \rm \ Pa[/tex]
Therefore, the new pressure of the gas is 388462 Pa.
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