Answer:
The magnitude of the force on an electron is 0.069 N.
Explanation:
Given that,
Distance between 1.70 A from the plutonium nucleus, [tex]d=1.5\times 10^{-12}\ m[/tex]
The number of electron in iron nucleus is +26e.
To find,
The magnitude of the force between an iron nucleus.
Solution,
Total charge in the plutonium nucleus is, [tex]q=26\times 1.6\times 10^{-19}=4.16\times 10^{-18}\ C[/tex]. The electric force between charges is given by :
[tex]F=\dfrac{kq^2}{d^2}[/tex]
[tex]F=\dfrac{9\times 10^9\times (4.16\times 10^{-18})^2}{(1.5\times 10^{-12})^2}[/tex]
F = 0.069 N
So, the magnitude of the force on an electron is 0.069 N. Hence, this is the required solution.
