Area of the doghouse =- 32.5 sq. ft
Solution:
Given height = 5 ft, base1, [tex]b_1[/tex] = 5ft
Base2, [tex]b_2[/tex] = [tex]b_1+3=5+3=8[/tex] ft
Area of the trapezoid = [tex]\frac{1}{2}\times height\times (base1 +base2)[/tex]
[tex]=\frac{1}{2}\times 5\times (5+8)[/tex]
[tex]=\frac{1}{2}\times 5\times 13[/tex]
[tex]=\frac{1}{2}\times 65[/tex]
[tex]=32.5[/tex] sq. ft
Area of the trapezoid = 32.5 sq.ft
Hence the area of the doghouse is 32.5 sq. ft.
