Answer:
n=0.03928 moles
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
Explanation:
The amount of oxygen which lung can have is 20% of 5 L which is the capacity of lungs
Volume of oxygen in lungs =V=5*20%= 1 L=[tex]1*10^{-3} m^3[/tex]
Temperature=T=[tex]37^oC=273+37=310K[/tex]
Pressure at sea level = P= 1 atm=[tex]1.0125*10^5 Pa[/tex]
R is universal Gas Constant =8.314 J/mol.K
Formula:
[tex]n=\frac{PV}{RT}\\n=\frac{(1.0125*10^5) *(1*10^{-3})}{(8.314)*310} \\n=0.03928 mol[/tex]
Moles of oxygen do the lungs contain at the end of an inflation are 0.03928 moles
