Answer:
Part 1) The sum of the two angles equals 70 degrees
Part 2) The complementary angle is 19 degrees and the supplementary angle is 109 degrees
Step-by-step explanation:
Part 1) we know that
The sum of the interior angles in any triangle must be equal to 180 degrees
so
In the triangle JKL
[tex]m\angle JKL+m\angle KLJ+m\angle LJK=180^o[/tex]
we have
[tex]m\angle JKL=110^o[/tex]
substitute
[tex]110^o+m\angle KLJ+m\angle LJK=180^o[/tex]
[tex]m\angle KLJ+m\angle LJK=180^o-110^o[/tex]
[tex]m\angle KLJ+m\angle LJK=70^o[/tex]
therefore
The sum of the two angles equals 70 degrees
Part 2) we know that
If two angles are complementary, then their sum is equal to 90 degrees
If two angles are supplementary, then their sum is equal to 180 degrees
step 1
Find the complementary
Let
c ----> the complementary angle
[tex]m\angle c+71^o=90^o[/tex]
[tex]m\angle c=90^o-71^o=19^o[/tex]
step 2
Find the supplementary
Let
s ----> the supplementary angle
step 1
Find the complementary
Let
c ----> the complementary angle
[tex]m\angle s+71^o=180^o[/tex]
[tex]m\angle s=180^o-71^o[/tex]
[tex]m\angle s=109^o[/tex]
therefore
The complementary angle is 19 degrees and the supplementary angle is 109 degrees
