Answer:
0.9 moles of Hg contain 5.418×10²³ atoms
Explanation:
As we know, Avogadro's number (NA) is the amount of particles that are contained in 1 mol → 6.02×10²³
Let's make a rule of three for this:
6.02×10²³ atoms are contained in 1 mol of Hg
5.418×10²³ atoms would be contained in (5.418×10²³ . 1) / NA = 0.9 moles
Answer:
We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercury
Explanation:
Step 1: Data given
Number of atoms of mercury = 5.418 * 10^23 atoms
Number of Avogadro = 6.022 *10^23 /mol
Step 2: Calculate number of moles of mercury
Moles mercury = number of atoms mercury / number of Avogadro
Moles mercury = 5.418 *10^23 /6.022*10^23 /mol
Moles mercury = 0.8997 moles
We have 0.8997 moles of mercury in 5.418 * 10^23 atoms of mercury
