Answer:
Explanation:
Given
Race length [tex]L=100\ m[/tex]
Runner reaches maximum velocity in [tex]t_1=2.4\ s[/tex]
[tex]v_{max}=11.3\ m/s[/tex]
distance traveled during this time
[tex]v=u+at[/tex]
[tex]11.3=0+a\times 2.4[/tex]
[tex]a=\frac{11.3}{2.4}=4.708\ m/s^2[/tex]
distance traveled in this time
[tex]s=ut+\frac{1}{2}at^2[/tex]
[tex]s=0+0.5\times 4.708\times (2.44)^2[/tex]
[tex]s=14.014\ m[/tex]
Remaining distance will be traveled with [tex]v_{max}[/tex]
remaining distance [tex]d=100-14.014=85.98\ m[/tex]
time taken [tex]t_2=\frac{d}{v_{max}}=\frac{85.98}{11.3}=7.609\ s[/tex]
total time [tex]t=t_1+t_2[/tex]
[tex]t=2.44+7.609=10.049\ s[/tex] Â Â Â Â
