Answer:
Option | and Option || is True
Step-by-step explanation:
Given:
If the square root of [tex]p^{2}[/tex] is an integer greater than 1,
Lets p = 2, 3, 4, 5, 6, 7..........
Solution:
Now we check all option for [tex]p^{2}[/tex]
Option |.
[tex]p^{2}[/tex] has an odd number of positive factors.
Let [tex]p=2[/tex]
The positive factor of [tex]2^{2}=4=1,2,4[/tex]
Number of factor is 3
Let [tex]p=3[/tex]
The positive factor of [tex]3^{2}=9=1,3,9[/tex]
Number of factor is 3
So, [tex]p^{2}[/tex] has an odd number of positive factors.
Therefore, 1st option is true.
Option ||.
[tex]p^{2}[/tex] can be expressed as the product of an even number of positive prime factors
Let [tex]p=2[/tex]
The positive factor of [tex]2^{2}=4=1,2,4[/tex]
[tex]4=2\times 2[/tex]
Let [tex]p=3[/tex]
The positive factor of [tex]3^{2}=9=1,3,9[/tex]
[tex]9=3\times 3[/tex]
So, it is expressed as the product of an even number of positive prime factors,
Therefore, 2nd option is true.
Option |||.
p has an even number of positive factors
Let [tex]p=2[/tex]
Positive factor of [tex]2=1,2[/tex]
Number of factor is 2.
Let [tex]p=4[/tex]
Positive factor of [tex]4=1,2,4[/tex]
Number of factor is 3 that is odd
So, p has also odd number of positive factor.
Therefore, it is false.
Therefore, Option | and Option || is True.
Option ||| is false.
