Respuesta :

TSO
ax^2 + bx + c = 0
-2x^2 + 6x + 13 = 0

a = -2
b = 6
c = 13

b^2 - 4ac

6^2 - 4(-2)(13)
= 36 - (-104)
= 36 + 104
= 140

The value of the discriminant is 140.
calculista

Let

D-------> discriminant of a quadratic equation

we know that

The discriminant of a quadratic equation is equal to

[tex] D=b^{2} -4ac [/tex]

In this problem

we have

[tex] -2x^{2} + 6x + 13=0\\ \\ a=-2\\ b=6\\c=13 [/tex]

Substitute the values in the formula above

[tex] D=6^{2} -4*(-2)*(13) [/tex]

[tex] D=36+104 [/tex]

[tex] D=140 [/tex]

therefore

the answer is

the value of the discriminant is [tex] 140 [/tex]

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