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The fifth term is t1 + 4d, where d is the common difference. Therefore we can write:
0 + 4d = 16
When you have solved for the value of d, just add zero and the value of d to find the second term.

Answer: Third option is correct.

Step-by-step explanation:

Since we have given that

[tex]t_1=0\\\\t_5=16[/tex]

Since they are in A.P., so it becomes,

[tex]t_5=0+(5-1)d\\\\t_5=4d\\\\16=4d\\\\d=\dfrac{16}{4}\\\\d=4[/tex]

So, second term of an A.P. would be

[tex]t_2=0+(2-1)\times 4\\\\t_2=0+4\\\\t_2=4[/tex]

Hence, Third option is correct.

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