The set of ordered pairs are [tex](-2,18),(-1,20),(0,22),(1,24),(2,26)[/tex]
Step-by-step explanation:
Given that the relation [tex]\{(x, y): y=2(x+11) \text { and } x \in(-2,-1,0,1,2)\}[/tex]
To find the set of ordered pairs, let us substitute the value for x in the relation [tex]y=2(x+11)[/tex]
For [tex]x=-2[/tex],
[tex]\begin{aligned}y &=2(-2+11) \\&=2(9) \\y &=18\end{aligned}[/tex]
The ordered pair is [tex](-2,18)[/tex]
For [tex]x=-1[/tex],
[tex]\begin{aligned}y &=2(-1+11) \\&=2(10) \\y &=20\end{aligned}[/tex]
The ordered pair is [tex](-1,20)[/tex]
For [tex]x=0[/tex],
[tex]\begin{aligned}y &=2(0+11) \\&=2(11) \\y &=22\end{aligned}[/tex]
The ordered pair is [tex](0,22)[/tex]
For [tex]x=1[/tex],
[tex]\begin{aligned}y &=2(1+11) \\&=2(12) \\y &=24\end{aligned}[/tex]
The ordered pair is [tex](1,24)[/tex]
For [tex]x=2[/tex],
[tex]\begin{aligned}y &=2(2+11) \\&=2(13) \\y &=26\end{aligned}[/tex]
The ordered pair is [tex](2,26)[/tex]
Thus, the set of ordered pairs is [tex](-2,18),(-1,20),(0,22),(1,24),(2,26)[/tex]
