A parking lot with an area of 9600ft^2 has a 200ft fence built along two adjacent sides of lengths x and y. If you were asked to find the dimensions of the parking lot, what equations would you used for the perimeter and area of the parking lot?

Answer:
[tex]\left\{\begin{array}{l}x+y=200\\ \\xy=9,600\end{array}\right.[/tex]
Step-by-step explanation:
The diagram shows rectangular parking lot with sides of [tex]x[/tex] feet and [tex]y[/tex] feet.
1. The area of the rectangle is
[tex]A=Length\times Width=xy.[/tex]
If the area of the parking lot os [tex]9,600\ ft^2,[/tex] then
[tex]xy=9,600[/tex]
2. A parking lot has a [tex]200\ ft[/tex] fence built along two adjacent sides of lengths [tex]x[/tex] and [tex]y[/tex], then
[tex]x+y=200[/tex]
3. The system of two equations describing this situation is
[tex]\left\{\begin{array}{l}x+y=200\\ \\xy=9,600\end{array}\right.[/tex]