Sarah bought 3 first class tickets and 7 coach tickets.
Step-by-step explanation:
Given,
Number of people = 10
Total amount spent on tickets = $4830
Cost of each coach ticket = $270
Cost of each first class ticket = $980
Let,
x be the number of coach tickets
y be the number of first class tickets
According to given statement;
x+y=10 Â Â Â Eqn 1
270x+980y=4830 Â Eqn 2
Multiplying Eqn 1 by 270
[tex]270(x+y=10)\\270x+270y=2700\ \ \ Eqn\ 3\\[/tex]
Subtracting Eqn 3 from Eqn 2
[tex](270x+980y)-(270x+270y)=4830-2700\\270x+980y-270x-270y=2130\\710y=2130[/tex]
Dividing both sides by 710
[tex]\frac{710y}{710}=\frac{2130}{710}\\y=3[/tex]
Putting y=3 in Eqn 1
[tex]x+3=10\\x=10-3\\x=7[/tex]
Sarah bought 3 first class tickets and 7 coach tickets.
Keywords: linear equation, elimination method
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