Respuesta :
Answer:
Incomplete question.
Complete question given below
a) 2.7933 C/s
b) 714.45 s
Explanation:
Even when shut down after a period of normal use, a large commercial nuclear reactor transfers thermal energy at the rate of 150 MW by the radioactive decay of fission products. This heat transfer causes a rapid increase in temperature if the cooling system fails {1 watt = 1 joule/second or 1 W = 1 J/s and 1 MW = 1 megawatt.
(a) Calculate the rate of temperature increase in degrees Celsius per second if the mass of the reactor core is 1.60105*10^6 kg and it has an average specific heat of 0.3349 kJ/kgº.
(b) How long would it take to obtain a temperature increase of which could cause some metals holding the radioactive materials to melt?
Part a)
[tex]Q_{rate} = m*c*\frac{dT}{dt}\\\frac{dT}{dt} = \frac{Q_{rate}}{m*c} \\\\\frac{dT}{dt} = \frac{150*10^6}{1.6 * 10^5*334.9} \\\\\frac{dT}{dt} = 2.7993 C/s[/tex]
Part b)
[tex]dt = \frac{dT}{2.7993} \\\\dt = \frac{2000}{2.7993} \\\\dt = 714.45 s[/tex]
