Answer:
The number of bacteria after [tex]8th[/tex] will be [tex]3840[/tex]
Step-by-step explanation:
Given the initially 30 bacteria present in the culture.
Also, the number of bacteria got doubled every hour.
So, using the equation
[tex]A=A_0r^{n-1}[/tex]
Where [tex]A[/tex] is number of bacteria after [tex]n[/tex] hours.
[tex]A_0[/tex] is bacteria present initially.
[tex]r[/tex] is the common ration, in our problem it is given that bacteria doubles every hour. So, [tex]r=2[/tex]
And [tex]n[/tex] is the number of hours. In our problem we need amount of bacteria at the end of [tex]8th[/tex] hours. So, [tex]n=8[/tex]
Plugging values in the formula we get,
[tex]A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840[/tex]
So, number of bacteria after [tex]8th[/tex] will be [tex]3840[/tex]