The number of bacteria in a certain culture doubled every hour. If there were 30 bacteria present in the culture initially, how many bacteria will be present at the end of the 8th hour?

Respuesta :

Answer:

The number of bacteria after [tex]8th[/tex] will be [tex]3840[/tex]

Step-by-step explanation:

Given the initially 30 bacteria present in the culture.

Also, the number of bacteria got doubled every hour.

So, using the equation

[tex]A=A_0r^{n-1}[/tex]

Where [tex]A[/tex] is number of bacteria after [tex]n[/tex] hours.

[tex]A_0[/tex] is bacteria present initially.

[tex]r[/tex] is the common ration, in our problem it is given that bacteria doubles every hour. So, [tex]r=2[/tex]

And [tex]n[/tex] is the number of hours. In our problem we need amount of bacteria at the end of [tex]8th[/tex] hours. So, [tex]n=8[/tex]

Plugging values in the formula we get,

[tex]A=30(2)^{8-1}\\A=30\times 2^7\\A=30\times 128\\A=3840[/tex]

So, number of bacteria after [tex]8th[/tex] will be [tex]3840[/tex]