Jose is standing 10 feet east of a mail-box when he begins walking directly east of the mailbox at a constant speed of 6 feet per second. A. How far east is Jose from the mail-box 5 seconds after he started walking?B. Write a formula that expresses Jose's distance from the mailbox (in feet),in terms of the number of seconds t since he started walking. C. As Jose walks away from the mail-box, is his distance from the mail-box proportional to the time elapsed since he started walking away from the mailbox?

Respuesta :

Answer:

a). 40 feet

b). 10 + 6t

c). Distance between the mail box and Jose is directly proportional to the time elapsed.

Step-by-step explanation:

Jose is standing 10 feet east of a mail box. If he starts walking with a constant speed 6 feet per second east of the mail box then

a). Distance traveled in 5 seconds with the same speed of 6 feet per second

= (6×5)

= 30 feet

Therefore, distance from the mail box = 10 + 30 = 40 feet

b). In time t distance traveled by Jose = Speed × Time

= 6t meter

Distance between mail box and Jose = (10 + 6t) meter

Formula will be, [tex]S_{t} =10+6t[/tex]

c). From the given formula,

[tex]S_{1} =10+6\times 1=16[/tex]

[tex]S_{2} =10+6\times 2=22[/tex]

We can observe that with the increase in time, Jose distance from the mail box is increasing.

Therefore, S ∝ t.