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In a 4.00 L pressure cooker, water is brought to a boil. If the final temperature is 115 °C at 3.10 atm, how many moles of steam are in the cooker?

Respuesta :

Eduard22sly

Answer: 0.39mol of the steam are in the cooker.

Explanation:Please see attachment for explanation

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Cricetus

The number of moles will be "0.39 mol".

Given:

  • Volume, V = 4 L
  • Pressure, P = 3.10 atm
  • Temperature, T = 115°C

                                   = 115+273

                                   = 388 K

We know the relation,

→ [tex]PV = nRT[/tex]

or,

→     [tex]n = \frac{PV}{RT}[/tex]

By substituting the values, we get

          [tex]= \frac{4\times 3.1}{0.082\times 388}[/tex]

          [tex]= 0.39 \ mol[/tex]

          [tex]= 0.39 \ mol[/tex]

Thus the above answer is correct.

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