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The molecular weight of calcium carbonate, CaCO3, is 100.09 3.
mol
How many moles of calcium carbonate are in 63.8 g of calcium carbonate?
Express the answer using 3 significant figures.

Respuesta :

jsmartojax

Answer:

Number of Moles = Reacting mass / Molecular mass

                              = 63.8 / 100.09

                              = 0.637g

Hence, the moles of calcium carbonate  in 63.8 g of calcium carbonate is 0.637g

Explanation:

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